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Need help with linear relationships question

Need help with linear relationships question-example-1
User Greg Combs
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1 Answer

3 votes

Answer:

The y-intercept (b) is - 5

The x-intercept is (5/3)

Explanation:

We are told this is a linear relationship, so lets look for a straight line equation in the form of y = mx + b, where m is the slope and b is the y-intercept, the goal of this question. Slope, m, is the Rise/Run, or rate of change, of the line. Calculate the slope by selecting any two points and find the Rise and Run. Let's use (2,1) and (7,16):

Rise = 16 - 1 = 15

Run = 7 - 2 = 5

Rise/Run (Slope, m) = 15/5 or 3

The equation becomes y = 3x + b.

To find the value of b, enter any of the given points for x and y and solve for b. Let's use point (2,1), since it makes the calculation easy:

y = 3x + b

1 = 3*2 + b for (2,1)

1 = 6 + b

b = -5

The y-intercept (b) is - 5. The full equation is y = 3x - 5

The x-intercept can be found by solving for x when the value of y is zero:

y = 3x - 5

0 = 3x - 5 for y = 0

-3x = -5

x = (5/3) The x-intercept is ((5/3),0)

See the attached graph.

Need help with linear relationships question-example-1
User Gerric
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7.6k points