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Question 8, MML C
Find the zeros of the quadratic function.
y = 21x² - 46x + 24

User Ali Salehi
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Final answer:

To find the zeros of the quadratic function y = 21x² - 46x + 24, you can use the quadratic formula. The zeros are approximately x ≈ 1.3333 and x ≈ 0.8571.


Step-by-step explanation:

To find the zeros of a quadratic function, you need to set the function equal to zero and solve for x. In this case, the function is y = 21x² - 46x + 24. Set y equal to zero:

0 = 21x² - 46x + 24

Next, you can factor the quadratic equation or use the quadratic formula to find the zeros. Let's use the quadratic formula:

x = (-b ± √(b² - 4ac)) / (2a)

Substituting the values from the given quadratic equation, you get:

x = (-(-46) ± √((-46)² - 4(21)(24))) / (2(21))

Simplifying further, you can calculate the values of x:

x = (46 ± √(2116 - 2016)) / 42

x = (46 ± √100) / 42

x = (46 ± 10) / 42

So, the zeros of the quadratic function are:

x = (46 + 10) / 42 = 56 / 42 =

x ≈ 1.3333

x = (46 - 10) / 42 = 36 / 42 =

x ≈ 0.8571


Learn more about Finding zeros of a quadratic function

User Jefsmi
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