Work is done when lifting an object because the force applied (equal to its weight) causes displacement in the direction of the force. The work done equals the weight of the object times the height lifted, and it's calculated as W = mgh. This work is stored as gravitational potential energy within the object.
When an object is lifted against the force of gravity, work is performed. The force exerted must be equal to the object's weight, which is the product of its mass (m) and the acceleration due to gravity (g), resulting in W = mg. For work to be done, there must be displacement in the direction of the force. Thus, lifting an object straight up involves a force acting upwards while the displacement is also upwards. The amount of work done on the object by lifting it is calculated as the product of the force and displacement in the same direction, W = Fd = mgh, where h is the height the object is lifted.
Generally, if the direction of the force and the displacement of an object are the same, the work done is positive, indicating that energy is transferred to the object. Lifting an object up increases its gravitational potential energy, which can later be converted back into kinetic energy if the object is allowed to fall.
The complete question is- Provide a detailed report on the activity of lifting an object up. Explain how work is done in this process, specifically addressing the force exerted, the direction of displacement, and the influence of gravity on the object.