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For how long must a frictional force of 5.6 N act in order to

bring to rest a mass of 2.4 kg moving at 6.0 m/s north? (3)

User Halllo
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1 Answer

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Final answer:

The frictional force must act for 1 second to bring the mass to rest.


Step-by-step explanation:

In this problem, we can use the equation:

Force = mass × acceleration

The frictional force acting on the object is opposing its motion, so the acceleration is in the opposite direction as well. Therefore, we have:

Frictional force = mass × (-acceleration)

Here, the mass of the object is 2.4 kg and the initial velocity is given as 6.0 m/s, which means the initial acceleration is 0 m/s^2. Since the object needs to be brought to rest, the final velocity is 0 m/s. Rearranging the equation, we get:

Final velocity = Initial velocity + acceleration × time

Plugging in the values, we have:

0 m/s = 6.0 m/s + (-acceleration) × time

Solving for time, we find that the frictional force must act for 1 second in order to bring the mass to rest.


Learn more about Frictional force and bringing an object to rest

User Dontocsata
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