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the wavelength of an x-ray photon is doubled on being scattered through 90o with a carbon block in a compton experiment. find out the wavelength of the incident photon

User Ndfred
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The scattered wavelength of X-rays in a specific direction can be determined using the equation λ' = λ + 2 x Aλ x cos(θ), where λ' is the scattered wavelength, λ is the incident wavelength, Aλ is the Compton shift, and θ is the scattering angle. In this case, the scattered wavelength in the direction making 90° with the incident beam is 1.0Å.

The scattered wavelength of X-rays can be determined using the equation:

λ' = λ + 2 x Aλ x cos(θ)

Where:

  • λ' is the scattered wavelength
  • λ is the incident wavelength
  • Aλ is the Compton shift
  • θ is the scattering angle

In this case, the incident wavelength is 1.0Å and the scattering angle is 90°. To find the scattered wavelength, we substitute these values into the equation:

λ' = 1.0Å + 2 x Aλ x cos(90°)

Since cos(90°) = 0, the equation simplifies to:

λ' = 1.0Å

Therefore, the scattered wavelength in the direction making 90° with the incident beam is 1.0Å.

--The given question is incorrect, the correct question is

"X-rays of 1.0A⁰are scattered from a carbon block. The wavelength of the scattered beam in a direction making 90⁰with the incident beam is ."--

User Jmccartie
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