Question

In ΔABC, a = 1.2 inches, b = 5.4 inches and c=4.7 inches. Find the measure of ∠C to the nearest 10th of a degree.

Answer 1

The measure of the angle C to the nearest 10th of a degree is 49.0 degrees

How to calculate the measure of angle C?

In the triangle given from the question, the following were obtained

• Side a = 1.2 inch
• Side b = 5.4 inch
• Side c = 4.7 inch
• Measure of angle C = ?

The measure of angle C by using the cosine rule formula as illustrated below:

`Cos\ C = (a^2\ +\ b^2\ -\ c^2)/(2ab) \\\\Cos\ C = (1.2^2\ +\ 5.4^2\ -\ 4.7^2)/(2\ *\ 1.2\ *\ 5.4) \\\\Cos\ C = 0.6566\\\\Take\ the\ inverse\ of\ Cos\\\\C = Cos^(-1)\ 0.6566\\\\C = 49.0\ \textdegree`

Thus, the measure of angle C is 49.0°

Complete question:

See attached photo