Question

The number of accidents that occureach day at a certain intersection alongwith the corresponding probabilities areshown.Accidents01234Probability.935.03.02.01.005Find the expected number of accidentseach day.

Answer 1

0.12

Step-by-step explanation:

The expected value of a probability distribution can be obtained using the formula:

`\sum ^n_(i\mathop=1)x_i\cdot P(x_i)`

Therefore, the expected number of accidents will be:

`\begin{gathered} E(X)=(0*0.935)+(1*0.03)+(2*0.02)+(3*0.01)+(4*0.005) \\ =0+0.03+0.04+0.03+0.02 \\ =0.12 \end{gathered}`

The expected number of accidents each day is 0.12.