Question

What is the equation of the line that passes through the point (4, 9) with a slope of - 5/8 Write the equation in point-slope form.

Answer 1

the slope of the line is -5/8 and it is passing through (4, 9)

the equation of a line is

`y-9=m(x-4)`

put m = -5/8

`\begin{gathered} y-9=-(5)/(8)(x-4) \\ y-9=-(5)/(8)x+(1)/(2) \end{gathered}`

so the equation of line is

y = -5/8 x + (1/2) + 9

y = -5/8 x + 19/2