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what would be the value of the mean for a binomial distribution that 93 trials and a success probability of 22%

User Jlajlar
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1 Answer

5 votes

Answer:

E(x) = 20.46

Explanation:

To find the mean value, use the formula E(x) = np

Where E(x) is the mean, or expected value, n is the number of trials and p is the probability of the event occurring.

In this case, our n is 93 and our p is 0.22. Hence:

E(x) = 93 × 0.22

E(x) = 20.46

Hope that helps!

User Maurera
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