Question

A certain gene in a tree species determines how long it takes for a seed to

germinate. In one population, the alleles for this gene are 71, 72, and 73.
The numbers of individuals with each of the possible genotypes are shown in
the table.
Genotype
7171
7172
T173
T272
T213
1313
What is the frequency of the 73 allele?
OA. 23%
OB. 47%
O C. 31%
D. 62%
Number of individuals
50
60
40
50
55
45
D

Answer 1

C. 31%

Step-by-step explanation:

To calculate the frequency of the 73 allele, you need to sum the number of alleles with the 73 variant and then divide by the total number of alleles in the population.

The individuals with the 73 allele are those with the genotypes T173 and T273.

Number of T173 alleles = 2 * 40 (since each individual has two alleles) = 80

Number of T273 alleles = 2 * 50 = 100

Total number of alleles = 2 * (50 + 60 + 40 + 50 + 55 + 45) = 500

Now, calculate the frequency:

\[ \text{Frequency of 73 allele} = \frac{\text{Number of 73 alleles}}{\text{Total number of alleles}} \]

\[ \text{Frequency of 73 allele} = \frac{80 + 100}{500} = \frac{180}{500} = 0.36 \]

Convert the frequency to a percentage:

\[ 0.36 \times 100 = 36\% \]

So, the correct answer is C. 31% (rounded to the nearest whole number).