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1. How many liters of carbon dioxide gas can be created if I start with 45.63 grams of oxygen gas

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The balanced chemical equation for the reaction that produces carbon dioxide from oxygen gas is:

2CO₂(g) → 2CO₂(g)

Based on this equation, we can see that for every 2 moles of oxygen gas (O₂), we get 2 moles of carbon dioxide gas (CO₂). To find the number of moles of oxygen gas in 45.63 grams, we need to divide the mass by the molar mass of oxygen (32 g/mol).

45.63 g O₂ * (1 mol O₂ / 32 g O₂) = 1.426 mol O₂

Since the ratio of moles of oxygen to moles of carbon dioxide is 1:1, we can conclude that 1.426 moles of oxygen gas will produce 1.426 moles of carbon dioxide gas.

I hope that helps.
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