Question

5. On a roller coaster ride at an amusement park, a car travels from 7.6 m/s to 56 m/s in 3.0 seconds

a. What is the car's acceleration?
b. How much distance did the car travel in 3.0 seconds?
c. If the car continued this acceleration, how fast would it be traveling after 150 m?

Answer 1

The car's acceleration is 16.13 m/s², the distance traveled in 3.0 seconds is 125.8 m, and the final velocity after traveling 150 m would be 86.7 m/s.

Step-by-step explanation:

a. To find the car's acceleration, we can use the formula acceleration = (final velocity - initial velocity) / time. Plugging in the given values, we get acceleration = (56 m/s - 7.6 m/s) / 3.0 s = 16.13 m/s².

b. To find the distance traveled by the car, we can use the formula distance = (initial velocity + final velocity) / 2 * time. Plugging in the given values, we get distance = (7.6 m/s + 56 m/s) / 2 * 3.0 s = 125.8 m.

c. To find the final velocity of the car after traveling a distance of 150 m, we can rearrange the formula distance = (initial velocity + final velocity) / 2 * time to solve for final velocity. Plugging in the given values, we get final velocity = 2(distance / time) - initial velocity = 2(150 m / 3.0 s) - 7.6 m/s = 86.7 m/s.

Learn more about Acceleration on a roller coaster