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m = √√ ₁²²+k²

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Final answer:

The subject of the given expression m = √√ ₁²²+k² is k.


Step-by-step explanation:

The given expression is:

m = √√ ₁²²+k²

To find the subject, we need to solve for n.

Let's start by simplifying the expression:

  1. √ ₁²²+k² can be written as (₁²²+k²)1/2
  2. √√ (₁²²+k²)1/2 can be written as [(₁²²+k²)1/2]1/2
  3. [[(₁²²+k²)1/2]1/2]1/2 can be written as [[(₁²²+k²)1/2]1/2]1/2
  4. Continuing this process, we eventually simplify the expression to m = [(₁²²+k²)1/2]1/2

Now, let's substitute m with the given value in the problem to solve for n:

[(₁²²+k²)1/2]1/2 = m

To remove the square root, we need to raise both sides of the equation to the power of 2:

[(₁²²+k²)1/2]1/22 = m2

Simplifying further, we get ₁²²+k² = m2

Now, we can solve for n by subtracting ₁²² from both sides of the equation:

k² = m2 - ₁²²

Then, we can take the square root of both sides:

k = √(m2 - ₁²²)

So, the subject of the given expression is k.


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