Final answer:
The subject of the given expression m = √√ ₁²²+k² is k.
Step-by-step explanation:
The given expression is:
m = √√ ₁²²+k²
To find the subject, we need to solve for n.
Let's start by simplifying the expression:
- √ ₁²²+k² can be written as (₁²²+k²)1/2
- √√ (₁²²+k²)1/2 can be written as [(₁²²+k²)1/2]1/2
- [[(₁²²+k²)1/2]1/2]1/2 can be written as [[(₁²²+k²)1/2]1/2]1/2
- Continuing this process, we eventually simplify the expression to m = [(₁²²+k²)1/2]1/2
Now, let's substitute m with the given value in the problem to solve for n:
[(₁²²+k²)1/2]1/2 = m
To remove the square root, we need to raise both sides of the equation to the power of 2:
[(₁²²+k²)1/2]1/22 = m2
Simplifying further, we get ₁²²+k² = m2
Now, we can solve for n by subtracting ₁²² from both sides of the equation:
k² = m2 - ₁²²
Then, we can take the square root of both sides:
k = √(m2 - ₁²²)
So, the subject of the given expression is k.
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