To find the z-score, we can use the formula:
z = (x - μ) / σ
where - x is the given value (in this case, x = 102), - μ is the mean (overline x = 98), and - σ is the standard deviation (s = 2.1).
Substituting these values into the formula, we get:
z = (102 - 98) / 2.1
Simplifying the equation, we have:
z = 4 / 2.1
Calculating this, we find:
z ≈ 1.90
Therefore, the z-score for x = 102, with a mean of 98 and a standard deviation of 2.1, is approximately 1.90.
The z-score measures how many standard deviations an observation is from the mean. In this case, the value 102 is approximately 1.90 standard deviations above the mean of 98.