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What is an equation for the linear function whose graph contains the points (-1, -2) and (3, 10)?

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y+_=_(x+1)​

User Kolexinfos
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The equation for the linear function whose graph passes through the points (-1, -2) and (3, 10) in point-slope form is y + 2 = 3( x + 1 ).

The point-slope form of a line is expressed as;

( y - y₁ ) = m( x - x₁ )

Given that, the line contains the points (-1, -2) and (3, 10).

First, we determine the slope m.

Slope m = ( change in y ) / ( change in x )

Slope m = ( 10 - (-2) ) / ( 3 - (-1) )

Slope m = ( 10 + 2 ) / ( 3 + 1 )

Slope m = 12/4

Slope = 3

Plug the slope m = 3 and point (-1, -2) into the point-slope formula and simplify.

( y - y₁ ) = m( x - x₁ )

y - (-2) = 3( x - (-1) )

Simplifying, we get:

y + 2 = 3( x + 1 )

Therefore, the equation of the graph in point-slope form is y + 2 = 3( x + 1 ).

User Darksider
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