Final answer:
The zeros of the function f(x) = x² + 16 are ±4i.
Step-by-step explanation:
The zeros of the function f(x) = x² + 16 can be found by setting the function equal to zero and solving for x. In this case, we have x² + 16 = 0. Since x² is always non-negative, there are no real solutions to this equation. However, we can find complex solutions by factoring out -1 from x² + 16 = 0, giving us (x + 4i)(x - 4i) = 0. This leads to the complex solutions x = ±4i.
Learn more about Finding zeros of a quadratic function