47.6k views
0 votes
What is the equation in slope-intercept form of the line that passes through the

points (-5, -5) and (5, -1)?

1 Answer

2 votes

Answer:

Equation of the line: y = 2/5x - 3

Explanation:

The general equation of the slope-intercept form is given by:

y = mx + b, where:

  • m is the slope,
  • and b is the y-intercept.

Finding the slope (m):

We can first find the slope (m) using the slope formula, which is given by:

m = (y2 - y1) / (x2 - x1), where:

  • m is the slope,
  • (x1, y1) is one point on the line,
  • and (x2, y2) is another point on the line.

Thus, we can find the slope (m) by substituting (-5, -5) for (x1, y1) and (5, -1) for (x2, y2) in the slope formula:

m = (-1 - (-5)) / (5 - (-5))

m = (-1 + 5) / (5 + 5)

m = 4 / 10

m = 2/5

Thus, the slope of the line is 2/5.

Finding the y-intercept (b) and writing the equation of the line:

Now, we can find the y-intercept (b) by substituting (-5, -5) for (x, y) and 2/5 for m in the slope-intercept form:

-5 = 2/5(-5) + b

-5 = -10/5 + b

(-5 = -2 + b) + 2

-3 = b

Thus, the y-intercept of the line is -3.

Therefore, y = 2/5x - 3 is the equation of the line in slope-intercept form that passes through (-5, -5) and (5, -1).

User Marsu
by
8.1k points