Question

A wheel of radius 30.0 cm is rotating at a rate of 2.30 revolutions every 0.0810 s.Through what angle does the wheel rotate in 1.00 s?What is the linear speed of a point on the wheel’s rim?What is the wheel’s frequency of rotation?

Answer 1

Given data

*The given radius of the wheel is r = 30.0 cm = 0.30 m

*Rate of rotation is 2.30 revolutions every 0.0810 s

The angle of the wheel rotates in one second is calculated as

`\begin{gathered} \theta=(2.30*2\pi)*(1)/(0.0810) \\ =178.32\text{ radian} \end{gathered}`

Hence, the angle of the wheel rotating in one second is 178.32 radian

The formula for the linear speed of a point on the wheel's rim is given as

`v=r\omega`

Substitute the known values in the above expression as