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What are the zeros of the function y = 6x²-x-2?

A. X=-
C. X=-
1 2
3
WIN
1
OB. X=-
2' 3
D. x = -
WIN
33
1 1
3' 2
-IN
-IN
1 1
2

1 Answer

6 votes

Final answer:

The zeros of the function y = 6x²-x-2 are x = 1/2 and x = -2/3.


Step-by-step explanation:

The zeros of a function can be found by setting the function equal to zero and solving for x. In this case, we have the equation 6x²-x-2=0. To solve this quadratic equation, we can factor it or use the quadratic formula. Let's use the quadratic formula:

x = (-b ± √(b²-4ac)) / (2a)

For the equation 6x²-x-2=0, a = 6, b = -1, and c = -2. Plugging these values into the quadratic formula, we get:

x = (-(-1) ± √((-1)²-4(6)(-2))) / (2(6))

This simplifies to:

x = (1 ± √(1+48)) / 12

Which further simplifies to:

x = (1 ± √49) / 12

So the two zeros of the function are:

x = (1 + √49) / 12 = 1/2

x = (1 - √49) / 12 = -2/3


Learn more about Finding zeros of a quadratic function

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