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with a certain sum of money, a vendor was able to buy shirts at ₱100 each. if the price had been ₱4 less, he would have obtained 2 more shirts. how much money did the vendor have?

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Final answer:

If the vendor had a sum of money amounting to ₱100, he could buy shirts at ₱100 each.

Step-by-step explanation:

Let's assume that the vendor had ₱x as the sum of money. With this amount, the vendor was able to buy shirts at ₱100 each. If the price had been ₱4 less, he would have obtained 2 more shirts.

So, we can set up the equation:

₱x / ₱100 = ₱(x - 4) / ₱96

Now we can solve for x:

₱x / ₱100 = ₱(x - 4) / ₱96

Cross multiply:

₱96x = ₱100(x - 4)

Expand:

₱96x = ₱100x - ₱400

Subtract ₱100x from both sides:

₱96x - ₱100x = - ₱400

Simplify:

-₱4x = - ₱400

Divide both sides by -4:

x = 100

Therefore, the vendor had a sum of money amounting to ₱100.

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