Question

What volume of a 6.35 M stock solution do you need to prepare 100 mL of a 0.3277 M solution of HNO3?

Answer 1

`\huge{ \boxed{5.16 \: ml}}`

Step-by-step explanation:

The volume of stock solution required can be found by using the formula;

`C_1V_1 = C_2V_2`

where

C1 is the concentration of the stock solution

V1 is the volume of the stock solution

C2 is the concentration of the final solution

V2 is the volume of the final solution

From the question;

C1 = 6.35 M

C2 = 0.3277 M

V1 = ? mL

V2 = 100 mL

`V_1 = (C_2 * V_2)/(C_1)`

`\therefore V_1 = (0.3277 * 100)/(6.35) \\ = 5.16 mL`