Question

Calculate the value of the following algebraic expression: 3x² + (x - 1)(x + 1) + 3(x + 2) + 5 at x = -1.​

Answer 1

Sure, let's solve the given expression step by step at x = -1:

The provided expression is: 3x² + (x - 1)(x + 1) + 3(x + 2) + 5

Step 1: Firstly, substitute the value of x as -1 in the given expression:

= 3(-1)² + ((-1) -1)((-1) + 1) + 3((-1) + 2) + 5

Step 2: Simplify the expression:

= 3(1) + ((-2))(0) + 3(1) + 5

Step 3: Further simplify,

= 3 + 0 + 3 + 5

Step 4: Add all the values,

= 11

Therefore, the value of the given expression 3x² + (x - 1)(x + 1) + 3(x + 2) + 5 at x = -1 is 11.

Answer 2

11

Explanation:

given the expression

3x² + (x - 1)(x + 1) + 3(x + 2) + 5

substitute x = - 1 into the expression

= 3(- 1)² + (- 1 - 1)(- 1 + 1) + 3(- 1 + 2) + 5 ← evaluate parenthesis

= 3(1) + (- 2)(0) + 3(1) + 5

= 3 + 0 + 3 + 5

= 3 + 8

= 11