To solve this problem, let's utilize the formula related to the physics of falling objects. That is, the time (t) it takes for an object to fall from a height (h) under gravity (g) can be expressed with the intuition that the distance travelled can be derived from the relation h = 1/2 * g * t^2.
In this specific problem, we're given that the height of the skyscraper (h) is 952 feet and the gravitational acceleration (g) is approximately 32.2 feet/sec^2.
We're interested in the falling time (t), so let's rearrange our formula to solve for it. Thus, we get: t = sqrt(2h/g).
Substituting the values of h and g into this equation gives us: t = sqrt(2 * 952 / 32.2).
Calculating this and rounding the result to one decimal place gives a time to hit the ground of 7.7 seconds.
So, although the answers provided in the problem statement (9.5, 9.6, 9.7, and 9.8 seconds) do not include the calculated result, using the established physics formula and the provided values leads us to estimate that it would take approximately 7.7 seconds for the baseball to hit the ground from a 952 feet tall skyscraper.