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at the city museum child admission is $5.10 and adult admission is $8.20. On Sunday 184 tickets were sold for a total sales of $1245.30 how many child tickets were sold that day?​

User Namezero
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To answer this question, we can use the method of solving systems of linear equations.

Firstly, we note that the total number of tickets sold is composed of both adult tickets and child tickets. Therefore, we can express this relationship as:

c + a = 184

where `c` stands for the number of child tickets and `a` represents the number of adult tickets sold.

Next, we also have information about the total revenue, $1245.30. As child tickets cost $5.10 each and adult tickets cost $8.20 each, this can be expressed as:

5.10c + 8.20a = 1245.30

We now have a system of two equations that needs to be solved. We can solve it by substitution or elimination method.

First, let's solve the first equation for one variable, say c, then we get:

c = 184 - a

Substitute this into the second equation, then we get:

5.10*(184-a) + 8.20a = 1245.30

Solve it for a resulting into its numeric value. Substitute the value of a that you find into the first equation to get the value of c.

From solving the system of equations, we find that the number of child tickets sold (c) that day is 85.

User Vikdor
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