To solve this problem, we should create an equation describing the total amount of work done by Sydney and Tori.
We know that together, they paint one room in 8 hours. Individually, let's say Tori takes `t` hours, while Sydney takes `t - 2` hours.
The work done when painting the room is the same, whether done individually or together, we can represent this work as 1 (for one room).
When they work together, their combined work is given as:
```
1/t + 1/(t - 2) = 1/8
```
Where `1/t` represents the work done by Tori in one hour and `1/(t - 2)` represents the work done by Sydney in one hour. The combined work is equal to 1 room painted per 8 hours.
We can solve this equation to find the value of `t`, which is the time Tori takes to paint the room alone. For such equations, we typically use algebraic methods, such as simplifying the equation and possibly applying the quadratic formula if it is a quadratic equation.
When we solve this equation, we find the value of `t` is approximately 17.06 hours. This means it would take Tori roughly 17.06 hours to paint the room alone.
Knowing that Sydney could finish this job 2 hours faster than Tori, we subtract 2 from 17.06 and find Sydney would take approximately 15.06 hours to painting the room alone.
So, it will take around 17.06 hours for Tori to paint the room alone and around 15.06 hours for Sydney to paint the room alone.