Final answer:
The probability of producing a child with right-handedness from a cross between two heterozygous parents is 75%.
Step-by-step explanation:
The probability of producing a child with right-handedness from a cross between two heterozygous parents can be determined using a Punnett square. Since right-handedness (R) is dominant over left-handedness (r), the potential genotypes of the parents are RR and Rr. When these genotypes are crossed, the possible genotypes of the offspring are RR, Rr, and Rr. The probability of producing a child with right-handedness (RR or Rr) is therefore 3/4 or 75%.
Learn more about Probability and dominance in genetics