Question

Steve puts 2 white counters and 1 black counter in a bag. He then puts more black counters in the bag. He is going to take ome counter without looking. The probability that th. Ounter will be black is 3 over 4. How many more black coungers did steve put in th bg?

Answer 1

5

Step-by-step explanation:

let the extra black counters = x

`P(black)=(3)/(4)`

`(black\ counters)/(total\ counters) =(3)/(4)`

`(1+x)/(2+1+x) =(3)/(4)`

`(1+x)/(3+x) =(3)/(4)`

`4(1+x)=3(3+x)`

`4+4x=9+3x`

`x=5`

Answer 2

Steve put 2 more black counters in the bag.

Step-by-step explanation:

To find the number of black counters Steve put in the bag, we can set up an equation using the given information. Let x represent the number of additional black counters Steve put in the bag. The probability of drawing a black counter is the number of black counters in the bag divided by the total number of counters: (1 + x) / (2 + 1 + x) = 3/4. Cross multiplying gives 4(1 + x) = 3(2 + 1 + x). Solving this equation, we find that x = 2. So, Steve put 2 more black counters in the bag.