Answer:
....let x and y be the numbers
xy=-12
x+y=2
per substitution: x=(2-y)
replace x :
(2-y)y=-12
2y-y²=-12
-y²+2y+12=0
calculate delta
b²-4ac =2²-4(-1*12)= 52
delta = 52
(-b-vd)/2a =(-2-2V13)/-2=1+V13
(-b+Vd)/2a =(-2+2V13)/-2 = 1-V13
numbers (1+V13) , (1-V13)
we check
xy=-12
(1+V13)(1-V13)= 1-13=-12
x+y=2
(1+V13)+(1-V13) = 2