Final answer:
To find the other vertices of the square, calculate the length of a side using the distance formula and then use the symmetry of the square. To show parallel sides, calculate the slopes and compare. Each angle in the square is 90°.
Step-by-step explanation:
Part A
To find the other two vertices of the square, we need to find the length of a side of the square. Using the distance formula, we can calculate the length of AC: √[(10-2)^2 + (4-(-4))^2] = √(64+64) = √128 = 8√2. Since the square is symmetric, the length of BD is also 8√2. Now, we can find the coordinates of B and D:
B = (10, 4+8√2) = (10, 4+8√2)
D = (2, -4-8√2) = (2, -4-8√2)
Part B
b. To show that AD is parallel to BC, we can calculate the slopes of AD and BC. The slope of AD is (∆y/∆x) = ((-4-4) / (2-10)) = -8/-8 = 1. The slope of BC is ((4-4-8√2) / (10-2)) = (-8√2 / 8) = -√2. Since the slopes are the same, AD || BC.
To show that AB is parallel to DC, we can calculate the slopes of AB and DC. The slope of AB is ((-4-4) / (2-10)) = -8/-8 = 1. The slope of DC is ((-4-(-4-8√2)) / (2-10)) = (-8√2 / -8) = √2. Since the slopes are the same, AB || DC.
c. Since AD || BC and AB || DC, the opposite sides of the square are parallel. Therefore, each angle inside the square is equal to 90°, making it a right angle.
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