Concentration of sugar
Given,
=
20
g
Molarmassofsolute
(
C
12
H
22
O
11
)
=
12
×
12
+
22
×
1
+
11
×
16
=
342
g
/
m
o
l
(
i
n
L
)
=
2
We know,
Molarity(M)
=
Number of moles of solute
Volume of solution in liters
=
Massofsugar
Molarmassofsugar
2
L
=
20
g
342
g
2
L
=
0.02925
m
o
l
L
−
1
Final answer:
=
0.02925
m
o
l
L
–
1