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Help me please it’s in the picture

Help me please it’s in the picture-example-1
User Amit Shah
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1 Answer

3 votes

Answer:


S(t) =(16)/(9)\pi t^4

Explanation:

The surface area (S) in square meters of a hot-air balloon is given by


S(r) = 4\pi r^2

where r is the radius of the balloon (in meters).

The radius (r) is increasing with time (t) in seconds according to the formula:


r(t) = (2)/(3)t^2, \quad t\geq 0

To find the surface area (S) of the balloon as a function of time (t), we can simply substitute the expression for the radius r(t) into the formula for S(r):


S(t) = 4\pi \left((2)/(3)t^2\right)^2

Now, simplify this expression:


S(t) = 4\pi \cdot(2^2)/(3^2)(t^2)^2


S(t) = 4\pi \cdot (4)/(9)t^4


S(t) =(16)/(9)\pi t^4

So, the surface area (S) of the hot-air balloon as a function of time (t) is:


\large\boxed{\boxed{S(t) =(16)/(9)\pi t^4}}

User Ben Companjen
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