Answer:
262 ml of 0.100 M HNO3 are needed to neutralize 34.7 mL of 0.775 M NaOH
Step-by-step explanation:
Because the reaction ratio of nitric acid and NaOH is 1:1, the calculation is fairly simple. The question now becomes "how many moles of NaOH are there, and how many milliliters of 0.1M HNO3 is equal to that many moles?"
Remember that:
n = M*V, where n = number moles, M = molarity, V = volume
n = 0.0347*0.755= 0.0262 moles NaOH (remember to use liters, not ml in calculations)
0.0262 moles HNO3 = 0.1 * V
V can be calculated easily to be 0.262 L, or 262 ml
Double check that sig figs are correct, and they are (3 sig figs), and you're done!