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12/90x(6x+1)=(7x-2)x2/7

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Answer:

Explanation:

First, simplify both sides of the equation: [ \frac{{12}}{{90}}x(6x + 1) = \frac{{(7x - 2)x^2}}{{7}} ]

Multiply both sides by 90 to get rid of the fraction: [ 12x(6x + 1) = 10x(7x - 2) ]

Distribute on both sides: [ 72x^2 + 12x = 70x^2 - 20x ]

Move all terms to one side: [ 72x^2 + 12x - 70x^2 + 20x = 0 ] [ 2x^2 + 32x = 0 ]

Factor out the common factor of 2x: [ 2x(x + 16) = 0 ]

Set each factor equal to zero and solve for x:

(2x = 0), which gives (x = 0)

(x + 16 = 0), which gives (x = -16)

Therefore, the solutions to the equation are (x = 0) and (x = -16).

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