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How many sodium ions are present in 100 ml of 0.1 M NaOH solution?

User Bgee
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1 Answer

6 votes

Answer:

About 6.022*10^21

Step-by-step explanation:

To find the number of sodium ions, we first need to find the number of moles. The number of moles can be found by the equation:
n = M*V
where
n = number of moles
M = molarity
V = volume (In liters, not milliliters!)
n = 0.1 * 0.1 = 0.01 moles
if you remember, 1 mole = 6.022*10^23 units
Because there is only 1 sodium ion per NaOH, there are 0.01 * 6.022*10^23 atoms, which equals 6.022*10^21 atoms/ions.

User MoRe
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