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STATE: How heavy a load (in pounds) is needed to pull apart pieces of Douglas fir 4 inches long and 1.5 inches square? Data

from students doing a laboratory exercise are given.
Weight of Load (lbs)
31,860
33,020
30,930
30,170
33,190
32,320
23,040
24,050
32,590
32,030
32,720
31,300
26,520
30,460
33,650
28,730
33,280
32,700
32,340
31,920
To access the data, click the link for your preferred software format.
CSV Excel (xls) Excel (xlsx) JMP Mac-Text Minitab14-18 Minitab18+ PC-Text R SPSS TI CrunchIt!
PLAN: We will estimate 4 by giving a 90% confidence interval.
SOLVE: Give a 90% confidence interval for the mean load required to pull apart the wood. Suppose that the strength of pieces
of wood like these follows a Normal distribution with standard deviation 3000 pounds. Give your answers to two
decimal places.

User Larspars
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1 Answer

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Final answer:

To estimate the mean load required to pull apart the wood, calculate a 90% confidence interval using the given data and a standard deviation of 3000 pounds.


Step-by-step explanation:

To estimate the mean load required to pull apart the wood, we can calculate a 90% confidence interval. Given a standard deviation of 3000 pounds, we will use a normal distribution. Using the given data, we can calculate the mean and standard error. The formula for a 90% confidence interval is:

Confidence Interval = mean ± (critical value * standard error)

Once the confidence interval is calculated, we can determine the range within which we are 90% confident the true mean load lies.


Learn more about Estimating the mean load required to pull apart pieces of wood

User Ioan M
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