Question

19) The original Ferris wheel, built by George Ferris for the Columbian

Exposition of 1893, was much larger and slower than its modern
counterparts. It had a diameter of 250 feet and contained 36 cars, each of
which held 40 people. It made one revolution every 10 minutes.
How far, to the nearest foot, does a passenger in a car travel
when the wheel makes on revolution? (2 points)

Answer 1

The distance a passenger in a car travels when the Ferris wheel makes one revolution is approximately 31,415 feet.

Step-by-step explanation:

The distance a passenger in a car travels when the wheel makes one revolution can be calculated using the formula for circumference of a circle. The formula is C = 2πr, where C is the circumference and r is the radius. The radius can be found by dividing the diameter by 2, so for this Ferris wheel, the radius is 250/2 = 125 feet. Plugging this value into the formula, we get C = 2π(125) = 250π feet. To find the distance to the nearest foot, we can multiply this value by 40 (the number of cars) and round to the nearest foot. Therefore, the passenger in a car travels approximately 31,415 feet when the Ferris wheel makes one revolution.

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