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36 votes
Write an equation for the line that passes through the given point and is perpendicular to the graph of the given equation y=-2x-1; (2, -1)

User Screamer
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1 Answer

27 votes
27 votes

The product of the slopes of the perpendicular lines = -1

If the slope of one is m, then the slope of the other is -1/m

The given equation is y = -2x - 1

The form of the equation is y = m x + b, where

m is the slope of the line

So the slope of the given line is m = -2

To find the slope of the perpendicular line reciprocal it and change its sign

The slope of the perpendicular line = 1/2

Substitute it in the form of the equation

y = 1/2 x + b

To find b substitute x and y of the equation by the coordinates of any point on the line

The line passes through point (2, -1), then

x = 2 and y = -1

-1 = 1/2 (2) + b

-1 = 1 + b

Subtract 1 from both sides to find b

-1 - 1 = 1 - 1 + b

-2 = b

The equation of the perpendicular line is

y = 1/2 x - 2


y=(1)/(2)x-2

User Abresas
by
3.4k points
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