Question

The equation for the area of a trapezoid is a = 27. if a = 18, b1 = 5, and b2 = 7, what is the height of the trapezoid? oh = 1.5 oh =3 oh = 6 oh=7

Answer 1

The height of the trapezoid is 3 units.

Step-by-step explanation:

The formula for the area of a trapezoid is A = (b1 + b2) * h / 2, where b1 and b2 are the lengths of the parallel bases and h is the height of the trapezoid.

Given A = 18, b1 = 5, and b2 = 7, we can substitute these values into the formula and solve for h.

18 = (5 + 7) * h / 2

18 = 12h / 2

18 = 6h

h = 18 / 6

h = 3

Therefore, the height of the trapezoid is 3 units.

Answer 2

The correct option is oh = 3.

The formula for the area A of a trapezoid is given by:

`\[ A = (1)/(2)h(b_1 + b_2) \]`

where h is the height, and
`\(b_1\) and \(b_2\)` are the lengths of the bases.

In your case, you have
`\(A = 18\), \(b_1 = 5\), and \(b_2 = 7\)`. Let's substitute these values into the formula:

`\[ 18 = (1)/(2)h(5 + 7) \]`

Now, solve for h:

`\[ 18 = (1)/(2)h(12) \]`

Multiply both sides by 2 to isolate h:

`\[ 36 = 12h \]`

Divide both sides by 12 to find h:

`\[ h = 3 \]`

So, the height of the trapezoid is 3.