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Find the center and the radius of the circle whose equation is x^2+y^2+8x-10y-23=0

Find the center and the radius of the circle whose equation is x^2+y^2+8x-10y-23=0-example-1
User Wolfcow
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2 Answers

11 votes
11 votes

Answer:the center would be (-4 -5)

Hope this helps

User Oleg Dok
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23 votes
23 votes

Finding the equation of the standard form:


\begin{gathered} x^2+y^2+8x-10y-23=0 \\ x^2+y^2+8x-10y=23 \\ x^2+8x+16+y^2-10y+25=23+16+25 \\ \\ \\ (x+4)^2+(y-5)^2=64 \end{gathered}

Based on the image, h = -4, k = 5 and r = 8, then...

Answer:

Center: ( -4, 5)

Radius: 8

Find the center and the radius of the circle whose equation is x^2+y^2+8x-10y-23=0-example-1
User Cardern
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2.7k points