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Show work please. tysm!!!!!!

Show work please. tysm!!!!!!-example-1
User EvilEddie
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1 Answer

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The measures of the angles and sides of the triangles listed from least to greatest are;

∆FGJ: m∠F = 41°, m∠H = 59°, m∠G = 80°

∆STU: m∠U = 29°, m∠S = 76°, m∠T = 79°

∆ANC: AC = 46, AB = 67, BC = 79

∆WXY: WY =13, WX = 20, XY = 36

There are three angles in a triangle and when all three angles are added together, they are equal to 180°. The perimeter of a triangle is the sum of all three side length of the triangle

For angles of triangles ∆FGH and ∆STU;

5x + 6 + 12x - 4 + 4x + 31 = 180°

21x + 33 = 180°

21x = 180° - 33° {subtract 33 from both sides}

x = 147/21

x = 7

m∠F = 5(7) + 6 = 41

m∠G = 12(7) - 4 = 80

m∠H = 4(7) + 31 = 59

7x - 36 + 5x - 1 + x + 9 = 180°

13x - 28 = 180°

13x = 180° + 28° {add 28 to both sides}

x = 208/13

x = 16

m∠S = 7(16) - 36 = 76

m∠T = 5(16) - 1 = 79

m∠U = 16 + 9 = 25

For the sides of triangles ∆ABC and ∆WXY;

6x - 35 + 4x + 11 + x + 29 = 192 {perimeter}

11x + 5 = 192

11x = 192 - 5 {subtract 5 from both sides}

x = 187/11

x = 17

AB = 6(17) - 35 = 67

BC = 4(17) + 11 = 79

AC = 17 + 29 = 46

9x - 7 + 12x - 1 + 3x + 4 = 68 {perimeter}

24x - 4 = 68

24x = 68 + 4 {add 4 to both sides}

x = 72/24

x = 3

WX = 9(3) - 7 = 20

XY = 12(3) - 1 = 36

WY = 3(3) + 4 = 13

Therefore, for triangles ∆FGJ and ∆STU, the angles from least to greatest are: m∠F, m∠H, m∠G and then m∠U, m∠S, m∠T respectively

∆. While the sides from least to greatest for the triangles ∆ANC and ∆WXY are: AC, AB, BC and then WY, WX, XY respectively.

User Barndog
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