Question

10. If the average of 6 distinct positive integers is

11, what is the largest possible integer could be one
of these integers?
E. 61 F. 51 G.41 H.31

Answer 1

To find the largest possible integer among 6 distinct positive integers with an average of 11, we can set up an inequality.

Step-by-step explanation:

To find the largest possible integer among 6 distinct positive integers with an average of 11, we can set up an inequality. Let the integers be a, b, c, d, e, and f. We know that (a + b + c + d + e + f) / 6 = 11. Multiplying both sides of the equation by 6 gives us a + b + c + d + e + f = 66. Since the integers must be distinct and positive, we can start from the largest number and subtract the other integers until we reach a sum of 66.

The largest possible integer could be one of these integers is 61.

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