Final Answer:
The solution to the system of linear equations (ax = b) may not always exist, contingent on the specific values of (a) and (b).
Step-by-step explanation
The existence of a solution to the system (ax = b) is contingent upon the properties of the matrix (a) and the vector (b). It's incorrect to assert that a solution invariably exists, regardless of the values of (a) and (b) (option a). Rather, it's the characteristics of (a) and (b) that determine the existence and uniqueness of a solution.
The solution's dependency on the values of (m) and (n) (option b) oversimplifies the matter. The critical factor is the nature of the matrix (a) (its rank, invertibility, etc.) and the relationship between (a) and (b) that dictate solution existence and uniqueness.
For instance, if (a) is a square matrix (same number of rows and columns), and it's invertible, a unique solution exists for any non-zero vector (b).
However, if (a) is not square or not invertible, the existence and uniqueness of a solution become more complex and may rely on the specifics of (b). Moreover, the solution isn't exclusively determined using Gauss-Jordan elimination (option d); various methods exist depending on matrix properties.