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If a weak acid is 91% neutralized at pH 5.7, what is the pka of the acid?

User Edna
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the pKa of the weak acid is approximately 5.82.

To determine the pKa of a weak acid, you need to know the concentration of the acid and its conjugate base at equilibrium.

In this case, since the weak acid is 91% neutralized, it means that 91% of the acid has dissociated to form its conjugate base. Therefore, the concentration of the conjugate base ([A-]) is 91% of the initial concentration of the acid ([HA]).

Now, let's assume the initial concentration of the acid is 1 mole. Since 91% of the acid has dissociated, the concentration of the conjugate base is 0.91 moles.

The equation for the dissociation of the weak acid can be written as follows:

HA ⇌ H+ + A-

Using the Henderson-Hasselbalch equation:

pH = pKa + log([A-]/[HA])

We know that at pH 5.7, the weak acid is 91% neutralized, so [A-]/[HA] = 0.91.

Therefore:

5.7 = pKa + log(0.91)

Rearranging the equation:

pKa = 5.7 - log(0.91)

Using a calculator, we find:

pKa ≈ 5.82

User Gaurang Deshpande
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