Question

I just need answers. No need longer to explain.Solve a

Answer 1

We need to find the period of the sinusoidal function in this case we have the next form

`y=A\sin (2\pi)/(T)(x+a)+b`

First, we need to find the amplitude in this case

`A=(5+1)/(2)=(6)/(2)=3`

The amplitude is 3

Then we need to find the period

`T=(2\pi)/(3)`

and the the displacement b is 2

Then for a we have

`a=(5)/(12)\pi`

Therefore we have

`y=3\sin 3(x-(5\pi)/(12))+2`

ANSWER

`y=3\sin 3(x-(5\pi)/(12))+2`