Answer and explanation:
There are many ways we can use this equation in a world problem and I'll provide three to demonstrate:
First world problem:
John receives an allowance of $45 from his parents and attends the county fair. The admission fee is $15. If the cost of each ride is $5, how many rides (x) can John go on?
- Solving would show us that John can go on 6 rides since 5(6) + 15 = 30 + 15 = 45.
Second world problem:
Stacey has been saving money for a certain number of weeks and already has $45 in her account. If she began with $15 in her account and adds $5 each week, how many weeks (x) has she been saving for?
- Solving would show us that Stacey has been saving for 6 weeks, since 5(6) + 15 = 30 + 15 = 45.
Third world problem:
A small city began with a population of 15 people and grew to 45 over a certain number of months. If 5 people moved into the city every week, how many weeks (x) did it take for the city to grow to 45 people?
- Solving would show us that it took 6 weeks for the city to grow to 45 people, since 5(6) + 15 = 30 + 15 = 45.