Question

Find all the zeros of the function.

y=x¹-6x² +8
(1 point)
+2, +√2
O ±1, t√√3
0,± √ √3
+4,+√√2
O

Answer 1

To find the zeros of the function y = x² - 6x + 8, we solve the quadratic equation x² - 6x + 8 = 0 using the quadratic formula. The zeros of the function are x = 4 and x = 2.

Step-by-step explanation:

The zeros of a function are the values of x for which y = 0. To find the zeros of the function y = x^2 - 6x + 8, we need to solve the equation x^2 - 6x + 8 = 0.

Using the quadratic formula, x = (-b ± √(b^2 - 4ac)) / (2a), we can plug in the values a = 1, b = -6, and c = 8:

x = (-(-6) ± √((-6)^2 - 4(1)(8))) / (2(1))

Simplifying, x = (6 ± √(36 - 32)) / 2

x = (6 ± √4) / 2

x = (6 ± 2) / 2

Now we have two solutions: x = (6 + 2) / 2 = 4 and x = (6 - 2) / 2 = 2.

Therefore, the zeros of the function are x = 4 and x = 2.

Learn more about Finding zeros of a quadratic function