Question

A golf ball is hit at ground level. The ball is

observed to reach its maximum height above
ground level 3.8 s after being hit. 1.2 s after
reaching this maximum height, the ball is
observed to barely clear a fence that is 213 ft
from where it was hit.
The acceleration of gravity is 32 ft/s².
How high is the fence?
Answer in units of ft.

Answer 1

The height of the fence is approximately 921.6 ft.

Step-by-step explanation:

To find the height of the fence, we need to calculate the time it takes for the golf ball to reach the ground from its maximum height. Since the ball reaches its maximum height 3.8 s after being hit, it will take the same amount of time to fall back down. So, the total time of flight is 3.8 s + 3.8 s = 7.6 s.

Using the equation d = v0t + (1/2)at2, where d is the distance, v0 is the initial velocity, t is the time, and a is the acceleration due to gravity, we can find the initial velocity.

With an initial velocity of 0 ft/s (the ball is hit at ground level), we have d = (1/2)(32 ft/s²)(7.6 s)2. Solving for d gives us the height of the fence as approximately 921.6 ft.

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