Question

The Keq for the equilibrium below is 7.52 x 10-2 at 480.0 °C.

2C12 (g) + 2H2O (g) 4HCI (g) + O2 (g)
What is the value of Keq at this temperature for the following reaction?
8HCI (g) +202 (g) 4C12 (g) + 4H2O(g)
1.77 x 102
7.52 x 10-2
5.66 x 10-3
-7.52 x 10-2
1.50 x 10-1

Answer 1

To track down the harmony consistent (Keq) for the given response, you can involve the connection between Keq values for a response and its converse response. The given response is the opposite of the first.

If Keq for \(2Cl_2(g) + 2H_2O(g) \rightleftharpoons 4HCl(g) + O_2(g)\) is \(7.52 \times 10^{-2}\), then the Keq for the converse response \(8HCl(g) + 2O_2(g) \rightleftharpoons 4Cl_2(g) + 4H_2O(g)\) is the complementary of the given Keq.

\[Keq_{\text{reverse}} = \frac{1}{Keq_{\text{forward}}} = \frac{1}{7.52 \times 10^{-2}}\]

Ascertain this worth to track down the Keq for the converse response.