Question

<1 and <2 are supplementary angles. If m<1 = (3x+18) and m<2 = (2x+17) then find the measure of <1

Answer 1

.....Supplementary angles are angles whose sum of measures is equal to 180°.

(3x+18)°+(2x+17)° = 180°.

3x+18+2x+17 =180

5x+35=180

5x=180-35

x=29°

m<1 = (3x+18)°

m1 = 3*29°+18°=105°

Explanation: