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If AQPZ ~ ASRZ, QZ = 15, PZ = x 7, RZ = 4, and SZ = x 3 find PZ.

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Final answer:

To find the length PZ, set up the proportion using the similarity of the triangles and solve for x. Disregarding the negative value, x = 3, and substituting back into PZ = x + 7 gives PZ = 10 units.

Step-by-step explanation:

If AQPZ is similar to ASRZ (denoted by AQPZ ~ ASRZ), we can set up proportions to find the length of PZ. Since triangle similarity means that corresponding sides are in proportion, we have:

· QZ/SZ = PZ/RZ

· 15/(x + 3) = (x + 7)/4

Now, we can cross-multiply to solve for x:

· 4 × 15 = (x + 3)(x + 7)

· 60 = x² + 10x + 21

Next, we solve the quadratic equation for x:

· x² + 10x + 21 - 60 = 0

· x² + 10x - 39 = 0

This equation factors to:

· (x + 13)(x - 3) = 0

Therefore, we get two potential solutions for x, x = -13 or x = 3. Since we are dealing with a length, we can disregard the negative value, leaving x = 3.

Now, we can substitute x back into PZ = x + 7:

· PZ = 3 + 7

· PZ = 10

The requested length PZ is 10 units.

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